Match the following:
CompoundOxidation number
$1$. $CrO_5$$a$. $+6$
$2$. $H_2SO_4$$b$. $+1$
$3$. $C_4OCl_2$$c$. $-1$
$4$. $(CH_3)_2SO$$d$. $+2$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The oxidation states are calculated as follows:
$1$. $CrO_5$ (Butterfly structure): The $Cr$ atom is bonded to four peroxo oxygen atoms ($-1$ each) and one double-bonded oxygen $(-2)$. Thus,$x + 4(-1) + 1(-2) = 0 \implies x = +6$. So,$1-a$.
$2$. $H_2SO_4$: $2(+1) + x + 4(-2) = 0 \implies x = +6$. So,$2-a$.
$3$. $C_4OCl_2$: This appears to be a typo in the question. Assuming the intended compound is $COCl_2$ (Phosgene),$x + (-2) + 2(-1) = 0 \implies x = +4$. Given the options provided,there is no match. If we consider the oxidation state of $Cl$ in $C_4OCl_2$,it is $-1$. So,$3-c$.
$4$. $(CH_3)_2SO$: $S$ is bonded to two methyl groups and one oxygen. $x + 2(0) + (-2) = 0 \implies x = +2$. So,$4-d$.
Correct matching: $1-a, 2-a, 3-c, 4-d$.

Explore More

Similar Questions

What is the oxidation number of the oxygen atom in the $O_2^{2-}$ ion?

The oxidation number of the underlined atom in the following species is given. Identify the incorrect option.

When $K_2Cr_2O_7$ is converted to $K_2CrO_4$,the change in the oxidation state of chromium is

The average oxidation state of sulphur in $Na_2S_2O_3$ is:

The oxidation number of $P$ in $Mg_3(PO_4)_2$ is ........

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo